Need calculus help with trigonometry

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Question description
1) solve the equation on the interval, [0,2pi) .
6 tan^2 x -17 tanx +7 =0
2) solve the equation on the interval, [0,2pi)
sinx = -2/3
3) 2 tan^2x -2 =0
4) olve the equation on the interval, [0,2pi)
(cot u +1)(csc u -1) = 0
u = ?
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